Giving out medals and fan...!Please help
In the following diagram, ΔABC is a right triangle.

Which statement explains why the sine of ∠A is equal to the cosine of ∠C?

The sum of the interior angles of a triangle is 180 degrees.

The triangle is a scalene right triangle and ∠A and ∠C are not right angles.

The acute angles in a right triangle are complementary, and the sine of an acute angle is equal to the cosine of its complementary angle.

The triangle is not proportional to itself so the trigonometric ratios do not apply.

Question

Giving out medals and fan...!Please help
In the following diagram, ΔABC is a right triangle.



Which statement explains why the sine of ∠A is equal to the cosine of ∠C?


The sum of the interior angles of a triangle is 180 degrees.


The triangle is a scalene right triangle and ∠A and ∠C are not right angles.


The acute angles in a right triangle are complementary, and the sine of an acute angle is equal to the cosine of its complementary angle.


The triangle is not proportional to itself so the trigonometric ratios do not apply.

mayaal · Answer

https://d3upxwx9bggvi1.cloudfront.net/img/questions/geogla_cc/geogla_16.png

anonymous · Answer

The acute angles in a right triangle are complementary, and the sine of an acute angle is equal to the cosine of its complementary angle.

mayaal · Answer

can u explain it to me?

anonymous · Answer

Sin is opposite over hypotenuse, cos is adjacent over hypotenuse; and to say two angles are complementary is to say they add up to 90 degrees. Since there are 180 degrees in a triangle, and we know that one angle is 90 degrees, then the other two must add up to 90 degrees.

mayaal · Answer

oh ok thank u very much :D

anonymous · Answer

My pleasure!