Medal and fan If the Ka of a conjugate acid is known, will the Kb base be strong or weak? It does not state if the conjugate acid is strong or weak.
@sweetburger @halorazer
Is it even possible to do this? O.o
No idea, that's why I'm asking.
@abb0t is god
But seriously bruh can you answer this because I have no idea. ;-;
If you know K\(_a\), you can most certainly find K\(_b\) with the known relationship I told you before: K\(_a\)(K\(_b\))=K\(_w\) and rearrange. You know K\(_w\) = \( \sf1.0 \times 10^{-14}\)
Is that supposed to be latex man
Do you know what K\(_a\) actually means?
Yessir. I don't know if my browser is displaying that all correctly though.
I don't know Ka...they don't give the value.
That's the whole issue here.
Ka is the acid dissociation constant. ;-; Let me try getting on chrome and see if I can see everything normally brbs
Ka * Kb=Kw, but she doesn't know what the actually Ka is. Otherwise we could definitely find the Kb.
K\(_a\) is an equilibrium constant for the partial ionization of "\(\color{red}{ weak}\)" acids in water
hence, the conjugate base of a weak acid is generally..
That's what I had thought but with chemistry, I seem to doubt myself unless I'm completely right. Thanks again!
Hannah, give him the medal. Not me. c:
Dude I did.
why tf do i still have a medal then
He probably gave you a medal
I'm just fabulous
Join our real-time social learning platform and learn together with your friends!