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Chemistry 15 Online
OpenStudy (anonymous):

Medal and fan If the Ka of a conjugate acid is known, will the Kb base be strong or weak? It does not state if the conjugate acid is strong or weak.

OpenStudy (anonymous):

@sweetburger @halorazer

OpenStudy (anonymous):

Is it even possible to do this? O.o

OpenStudy (anonymous):

No idea, that's why I'm asking.

OpenStudy (anonymous):

@abb0t is god

OpenStudy (anonymous):

But seriously bruh can you answer this because I have no idea. ;-;

OpenStudy (abb0t):

If you know K\(_a\), you can most certainly find K\(_b\) with the known relationship I told you before: K\(_a\)(K\(_b\))=K\(_w\) and rearrange. You know K\(_w\) = \( \sf1.0 \times 10^{-14}\)

OpenStudy (anonymous):

Is that supposed to be latex man

OpenStudy (abb0t):

Do you know what K\(_a\) actually means?

OpenStudy (anonymous):

Yessir. I don't know if my browser is displaying that all correctly though.

OpenStudy (anonymous):

I don't know Ka...they don't give the value.

OpenStudy (anonymous):

That's the whole issue here.

OpenStudy (anonymous):

Ka is the acid dissociation constant. ;-; Let me try getting on chrome and see if I can see everything normally brbs

OpenStudy (anonymous):

Ka * Kb=Kw, but she doesn't know what the actually Ka is. Otherwise we could definitely find the Kb.

OpenStudy (abb0t):

K\(_a\) is an equilibrium constant for the partial ionization of "\(\color{red}{ weak}\)" acids in water

OpenStudy (abb0t):

hence, the conjugate base of a weak acid is generally..

OpenStudy (anonymous):

That's what I had thought but with chemistry, I seem to doubt myself unless I'm completely right. Thanks again!

OpenStudy (anonymous):

Hannah, give him the medal. Not me. c:

OpenStudy (anonymous):

Dude I did.

OpenStudy (anonymous):

why tf do i still have a medal then

OpenStudy (anonymous):

He probably gave you a medal

OpenStudy (anonymous):

I'm just fabulous

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