Question

Ab is tangent to the circle , AD = 4, and BC = 3. Solve for x.

Answer 1

You can use secant tangent formula

Answer 2

AB^2 = AD * AC

Answer 3

\[x^2=4*4+x\]

Answer 4

or is the last part 4+3

Answer 5

4+3

Answer 6

Its radius :)

Answer 7

ok my answer is
x=5.29

Answer 8

correct

Answer 9

Good work :)

Answer 10

thank you

Answer 11

my choices are these
\[A.\sqrt{5}\]
\[B.5\]
\[C.2\sqrt{10}\]
\[D.\sqrt{58}\]

Answer 12

so my answer would be B.5 right?

Answer 13

yes

Answer 14

because A.2.23 C.6.32 D.7.61

Answer 15

Yeah

Answer 16

@vishweshshrimali5 ok just double checking

Answer 17

No no wait

Answer 18

You can't apply tangent secant theorem here

Answer 19

ok so what would i do?

Answer 20

You have to use Pythogoras theorem.

Remember that tangent always is perpendicular to radius.

Answer 21

\[3^2+x^2=7^2\]
\[9+x^2=49\]
\[x^2=40\]
\[x=6.32\]

Answer 22

\[\sqrt{40} = 2\sqrt{10}\]

Answer 23

right

Answer 24

Good

Answer 25

\[2\sqrt{10}=6.32\]

Answer 26

@vishweshshrimali5 thanks again

Answer 27

No problem