Question

Boolean algebra
Simplify
xy+x'yz'+yz

Answer 1

factor out y from first two terms

Answer 2

y(x+x'z')+yz
Just like that?

Answer 3

I think you can factor out the y from all three terms then you have y(x+x'z'+z) but we can re-write that y((x+z)+x'z') then use the identity (x+z) = (x'z')' to get
y((x'z')'+x'z') which is, of course, just y.

Answer 4

nice :)

@genson0 try below also :

y(x+x'z')+yz

y(x+z') + yz

y(x + z' + z)

y(x + 1)

y(1)

y

Answer 5

Thank you both @ganeshie8 and @Valpey ,, I appreciate the help. I wish I could give you both medals.