Question

Limit question:

Answer 1

\[\LARGE \lim_{x \rightarrow -\infty}(\sqrt{x^2+x+1}+x) \]

Answer 2

Rationalize.

Answer 3

-inf

Answer 4

-1/2 ?

Answer 5

my guess was wrong :O??

Answer 6

no doubt

Answer 7

lol

Answer 8

\[\LARGE \lim_{x \rightarrow -\infty}(\sqrt{x^2+x+1}+x)*(\sqrt{x^2+x+1}-x)\]
\[\LARGE \lim_{x \rightarrow -\infty} (x^2+x-1-x^2)\]
\[\LARGE \lim_{x \rightarrow -\infty}(x-1)\]
Did I screw up? xD

Answer 9

Whoops *+1

Answer 10

did you forget how to rationalize ? o.O you just multiplied but didn't divide.

Answer 11

it's -1/2

Answer 12

Yes I did xD

\[\LARGE \lim_{x \rightarrow -\infty} \frac{(x+1)}{\sqrt{x^2+x+1}-x}\]

Answer 13

okay now divide top and bottom by x

Answer 14

like he said

Answer 15

for denominator i'd help a bit
\[\LARGE \sqrt{(x^2(1+\frac{1}{x}+\frac{1}{x^2})} -x \]

Answer 16

x^2 will become x outside and then x will cancel out
Then use the fact that............
\[\Huge \lim_{x \rightarrow -\inf} \frac{1}{x^2} ,\frac{1}{x} ->0\]

Answer 17

=[ how do i type in latex

Answer 18

You forgot your "\"

Answer 19

\[hey\]

Answer 20

Alright, thank you guys :)

Answer 21

uw :)