What is the relative maximum and minimum of the function? f(x) = 2x2 + 28x - 8
A. Minimum Value: -7 Range y > -7 B. Minimum Value: 7 Range y > 7 C. Minimum Value: -106 Range y > -106 D. Minimum Value: -106 Range y > -7
find the vertex of this parabola
its a parabola facing upwards so, you can tell the minimum y value from the vertex
I don't know how to
and the Range, meaning all the other y values. will include every other y number greater than that min value
have you learnt about derivatives yet?
yes but I really didn't understand
I had thought B but it was wrong
for a parabola, the maximum or minimum happens when the derivative =0, because the tangent line there must be horizontal|dw:1403083206816:dw|
ok
f'(x) = ?
2x^2 +28x -8
f ' (x) = take the derivative of f(x)
use this formula for now it comes straight from differentiation -b/2a will give you the x value where the vertex is -28/4 = -7 y=2*(-7)^2+28*-7 -8 = 98 -140-56-8 = -106
therefre min value = -106, and the range of y is every value more or equal to that
so C??
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