how does applying heat impact of exothermic reactions? why does cause a net backwards reaction?
if you've studied equilibrium, you can consider the addition of heat to an exothermic reaction a stress to the products, so the reaction shifts backwards
a stress to the products? can u please explain that?
have you studied equilibrium? that's how i usually teach this kind of situation
yes i have :)
then you know about stresses to systems at equilibrium? leChatelier's principle?
i know lechatelier's principle: things acting opposite... but stresses im not too sure?
things "act opposite" when reactions are stressed. A stress is something like the addition of a product, or the removal of a reactant, that changes the concentrations at equilibrium and "unbalances" the system. The system will then shift to relieve the stress
can u please explain how heat impacts this?
i know that an increased temp will causeless products in exo thermic how? if i apply that acting in opposite thing, how does it apply with this example?
heat can be considered just like a reactant or a product in a reaction, so if you add heat to an exothermic reaction, it's just like adding too much of a product. So the reaction shifts backwards
increasing temp is adding het to product rather than reactant?
if the reaction is exothermic, heat is produced, right?
\[CH_4 + 2O_2 \rightarrow CO_2 + 2H_2O + energy\]
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