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Chemistry 11 Online
OpenStudy (anonymous):

Medal and fan How would you calculate the pH given the molarity of NaOH, or technically OH-?

OpenStudy (anonymous):

@Abhisar @JFraser @Somy

OpenStudy (somy):

luckily there there is a worked example of your question in my book lol

OpenStudy (somy):

second part

OpenStudy (anonymous):

Errr, that's in mol though, not molarity with a capital M. There wouldn't be any way to determine the liters.

OpenStudy (somy):

whats in mole?

OpenStudy (anonymous):

the concentration.

OpenStudy (somy):

its in moledm-3

OpenStudy (somy):

its unit of concentration

OpenStudy (anonymous):

Yess, I know. I need the molarity though, meaning m/L

OpenStudy (anonymous):

mol/L*

OpenStudy (somy):

dear lol Liter is dm3

OpenStudy (somy):

molarity and concentration are same thing unit is mole/dm3 or mole/L exact same thing

OpenStudy (anonymous):

Oh. I didn't know that.

OpenStudy (somy):

i didn't know it too when i just joined OS but here ppl use liters a lot so i got to know it somehow xD

OpenStudy (anonymous):

Okay, well I took the concentration, raised it -log^x (x being the number), then subtracted that number from 14. Wouldn't that be right?

OpenStudy (somy):

yeah i guess this is how it's saying

OpenStudy (somy):

in a quick way lol

OpenStudy (anonymous):

Alrighty then.

OpenStudy (somy):

is it clear? or should i post the part of where it kinda explains what you need to calculate it or so?

OpenStudy (anonymous):

No I understand that formula, I've used it before, I just wasn't sure if I was able to use it for molarity.

OpenStudy (somy):

cool then :D

OpenStudy (anonymous):

Thank ya(:

OpenStudy (somy):

no probs :D

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