Question

Determine the amount of heat (in kJ) required to vaporize 1.20kg of water at its boiling point. For water, ΔHvap = 40.7 kJ/mol (at 100 ∘C)

Answer 1

\[q= mc \Delta T\]

Answer 2

you actually dont need that formula above, this is just the heat required for the change in state and there is no temperature change. Use: \(q=\Delta H_{vap}*n\)

n=moles, btw.

Answer 3

owh lol didn't know this one @aaronq

Answer 4

q=40.7*1.20
is this correct?

Answer 5

no, you need to use the moles not the mass