Question

y^-2/y^2

can someone help me understand how to do this?

Answer 1

\[\frac{ y^-2}{ y^2 }\]

Answer 2

\(\Large y^{-2}=\frac{1}{y^2}\)
So, \(\Large \frac{y^{-2}}{y^2}=\huge \frac{\frac{1}{y^2}}{y^2}\Large= \frac{1}{y^2\times y^2}=\frac{1}{y^4}\)

Answer 3

\[y^{-2}=\frac{ 1 }{ y }\]
so(1/y^2)X(1/y^2)
=\[\frac{ 1 }{ y ^{4} }\]

Answer 4

ok

Answer 5

Thank you so much!

Answer 6

u r welcome