Two triangles can be formed with the given information. Use the Law of Sines to solve the triangles. B = 29°, b = 26, c = 28 A = 92.5°, C = 58.5°, a = 53.6; A = 87.5°, C = 121.5°, a = 53.6 A = 92.5°, C = 58.5°, a = 12.6; A = 87.5°, C = 121.5°, a = 12.6 A = 119.5°, C = 31.5°, a = 46.7; A = 2.5°, C = 148.5°, a = 2.3 A = 119.5°, C = 31.5°, a = 14.5; A = 2.5°, C = 148.5°, a = 14.5
Set up the equation for law of sines, sin29/26 = sinC/28 to find the angle of C.
After you find the angle of C, you can subtract the angles of C and B by 180 to find the angle of A.
okay give me a sec
Once you find the angle of A then use law of sines again to find the side of angle A by plugging it in.
im so lost lol
Alright give me a few seconds.
First triangle.
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We want to now find the angle of c since we are given it's side. So let's set up our equation. sin29/26 = sinc/28 When we solve we get 31.47 for the angle of c. Now we subtract that number by 180 and the angle of b to find the angle of a. So angle a = 119.5.
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Now we use law of sines again to find the side of a. We can use either the side and angle of B or C to solve for A. But since we know both the angle and side of B let's just use that instead. sin119.52/sidea = sin29/26 So our answer for the side of a is 46.
Therefore; angle C = 31.47 angle A = 119.5 side a = 46
theres no choice for a=46
A = 119.5°, C = 31.5°, a = 46.7; A = 2.5°, C = 148.5°, a = 2.3
46.67656571 is what I got on my calculator.
oh okay thank you so much !!!!!
Anytime.
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