Question

If MN = QR, then JK + MN = JK + QR.
@vzfreakz

Answer 1

What are your options.

Answer 2

@vzfreakz
symmetric property
substitution property
addition property
transitive property
reflexive property

Answer 3

I don't think it would be substitution.

Answer 4

@vzfreakz so what would you go with?

Answer 5

I'll let @ganeshie8 answer this.

Answer 6

MN = QR

Adding JK to both sides gives you :

JK + MN = JK + QR

Answer 7

So... clearly it is _________ property ?

Answer 8

@ganeshie8 addition property?

Answer 9

Yep ! good work !!

Answer 10

@ganeshie8 can you help me in something else? i have to upload images so you can see the problem so ill ask thru here is it fine?

Answer 11

I'll try, ask...

Answer 12

For the proof shown, provide statement 5
@ganeshie8

Answer 13

got options for this ?

Answer 14

@ganeshie8
a.

AB = DE

c.

BC = EF
b.

AB = EF

d.

AC = DF

Answer 15

No sir I do not. He asked this question to me earlier.

Answer 16

I forgot how to compute this property problem. It's been a while.

Answer 17

@vzfreakz yes the options are there .
i mentioned you in the other question the options .

Answer 18

Number 3 is Commutative of -.

Answer 19

its a trick question - we need to fill 5th statement using the 3rd and 4th statements

Answer 20

lets look at 3rd and 4th statements

Answer 21

3. \(\color{red}{AC - BC} = \color{green}{DF - EF}\)

4. \(\color{red}{AC - BC = AB}\)
\(\color{green}{DF - EF = DE}\)

Answer 22

Okay, this is what I got so far.

The general example would be a=b, then 'a' may be substituted for 'b', and conversely.

So, what I'm thinking is if (a+b)=c, then c may be substituted by any number.

Answer 23

Or it could be the other way around..

Answer 24

Exactly ! we need to substitute AB and DE in the 3rd statement

Answer 25

3. \(\color{red}{AC - BC} = \color{green}{DF - EF}\)

4. \(\color{red}{AC - BC = AB}\)
\(\color{green}{DF - EF = DE}\)

5. \(\large \color{red}{AB} = \color{green}{DE}\)

Answer 26

see if that looks okay...

Answer 27

I'm watching this video just to be sure we're right.

Answer 28

@ganeishie8 yes it does
can you help me with another one ?
and it is asking to provide statement 3

Answer 29

So, is the answer right?

Answer 30

Same here friend, same here.

Answer 31

Alright, so its not an exam right ?

Answer 32

You're talking to @trruhgnh, just to be sure.

Answer 33

yes

Answer 34

@ganeshie8 no its not its just assignments

Answer 35

okay, the last question is pretty easy -
heard of `transitive property` before ?

Answer 36

Transitive property :

If \(a = b\) and \(b = c\), then \(a = c\).

Answer 37

In second statement you're given below :
\(AB =CD\) and \(CD = EF\)

Answer 38

So by transitive property we can say :
\(\large AB = ?\)

Answer 39

AD? @ganeshie8

Answer 40

You guys go ahead an work on this. I'm done answering this lol.

Answer 41

and*

Answer 42

If \(AB =CD\) and \(CD = EF\) , then \(\large AB = EF\)

Answer 43

transitive property tells us to simply equate first and last parts.. ^