A line has a slope of –5 and a y-intercept of (0, 3). What is the equation of the line that is perpendicular to the first line and passes through the point (3, 2)?
Hi welcome to OpenStudy!! We're glad you're here :) Okay so do you know the rule on the slopes of perpendicular lines?
So in our first line, it tells us that the slope of it is -5. This means the slope of the line perpendicular to it is the negative reciprocal. How to find that is doing -1/slope. So the slope given is -5. So the slope of the line perpendicular to it is -1/-5. The negatives cancel making the slope of the line perpendicular to the other 1/5.
So we know this new line has a slope of 1/5 because it is perpendicular to the line with a slope of -5. It tells us that the line perpendicular to the other goes through the point (3,2).
thank ya XD jus know seen your replies
So it goes through point (3,2) and has a slope of 1/5. This is called point-slope form. When you are given a slope and a point (like we have here 1/5 is slope and point is (3,2)) we plug it into this to find our equation. |dw:1403114377445:dw|
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