Find the Inverse of f(x)= log(base 2) x-3
I assume you've covered logarithms by now?
Yes
well if you recall to find the "inverse relation" we simply swap about the variables, that is \(\bf f(x)={\color{brown}{ y}}=log_2({\color{blue}{ x}}-3)\qquad inverse\implies {\color{blue}{ x}}=log_2({\color{brown}{ y}}-3)\) then we just solve for "y" any ideas?
Not sure
\(\bf f(x)={\color{brown}{ y}}=log_2({\color{blue}{ x}}-3)\qquad inverse\implies {\color{blue}{ x}}=log_2({\color{brown}{ y}}-3) \\ \quad \\ \textit{log cancellation rule of }\large {\color{red}{ a}}^{log_{\color{red}{ a}}x}=x\qquad thus \\ \quad \\ x=log_2(y-3)\implies{ \large {\color{red}{ 2}}^x={\color{red}{ 2}}^{log_{\color{red}{ 2}}(y-3)}}\implies 2^x=y-3 \\ \quad \\ 2^x+3=y \iff f^{-1}(x)\)
Ok, so the inverse is solving for Y?
Thanks!
well..yes
yw
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