Question

Graph y = -2x +3 and its inverse.

Answer 1

answer choices

Answer 2

@jim_thompson5910

Answer 3

@jigglypuff314
@jdoe0001

Answer 4

if you recall, to find the "inverse relation" all we do is swap about the variables and solve for "y" so \(\bf {\color{brown}{ y}} = -2{\color{blue}{ x}} +3\qquad inverse\implies {\color{blue}{ x}}= -2{\color{brown}{ y}} +3\)

Answer 5

then just graph each :)

Answer 6

idk how to graph them

Answer 7

is it C??

Answer 8

ohh to graph them... just pick 2 random "x" and get a 'y" for each

each one is just a line thus 2 points will make a line
get the x,y for each random you picked and draw a line through them

Answer 9

ok I tried but I got C am I correct

Answer 10

hmmm what inverse function did you get?

Answer 11

i just tried by using slope -2 and i thought C or D but how do i use your method

Answer 12

well... parallel lines have the same slope, but that doesn't mean they have the same coordinates

so... .to graph them... the slope alone won't do it

Answer 13

oh ok but how do i do your method??

Answer 14

the inverse? notice, all I did was swap the variables \(\bf {\color{brown}{ y}} = -2{\color{blue}{ x}} +3\qquad inverse\implies {\color{blue}{ x}}= -2{\color{brown}{ y}} +3\)

then you need to solve for "y"

Answer 15

ok how do i solve for y

Answer 16

well... is just a linear equation.. I assume you've covered simplifying linears equations?

Answer 17

yeah but i had a lot of trouble with that

Answer 18

well for x=-2y+3

subtract 3 from both sides
then divide both sides by -2

see what you get

Answer 19

x-3/-2 = y

Answer 20

yeap

Answer 21

ok now what??

Answer 22

then just pick a couple of random "x" let's try for say the function itself

y = -2x+3 x=0
y = -2(0)+3
y=3

so the point will be (0,3)
-----------------------------------------
let's pick another random "x"

y= -2x+3 x=2
y=-2(2)+3
y=-4+3
y=-1

so the 2nd point for that will be (2, -1)

Answer 23

so you have two points for the first one, and since the equation is just a line, you can just draw a line through them

Answer 24

ok and then what

Answer 25

I got A

Answer 26

\(\bf x-3/-2 = y\\
\cfrac{x-3}{-2}=y\qquad x=0
\\ \quad \\
\cfrac{0-3}{-2}=y\implies \cfrac{3}{2}=y\\
\qquad \left(0,\cfrac{3}{2}\right)\\
----------------------\\
\cfrac{x-3}{-2}=y\qquad x=2
\\ \quad \\
\cfrac{2-3}{-2}=y\implies \cfrac{1}{2}=y\\
\qquad \left(2,\cfrac{1}{2}\right)\)

Answer 27

so was i correct A??

Answer 28

ahemm recheck your graph

Answer 29

D??

Answer 30

check your graph

Answer 31

im so confused is it the second graph??

Answer 32

well... did you graph them? do they look like the 2nd graph?

Answer 33

to me it looked like the last, what does yours look like

Answer 34

http://fooplot.com/#W3sidHlwZSI6MCwiZXEiOiItMngrMyIsImNvbG9yIjoiIzI2MTZERSJ9LHsidHlwZSI6MCwiZXEiOiIoeC0zKS8tMiIsImNvbG9yIjoiI0Q5MUMxQyJ9LHsidHlwZSI6MTAwMH1d yeap, looks like the last one :)

Answer 35

thank you so much you helped me a lot :)

Answer 36

yw