Question

Power System: Lesson

Answer 1

When it comes to power system we are familiar with unit like volt, amp,and watts but in power system there is a unit called "per unit"

Answer 2

Let's define base power as 100W , which mean any other power will be measure relative to this

Answer 3

200W will be 2 pu (per unit)

50 W will be .5 pu(per unit) so on

Answer 4

by defining two base unit (ie , power and current) , we can eliminate all other variable

Answer 5

Interesting, can you give an example of how you can remove all other variables? I'm familiar with the relation P=IE (power, current, voltage) so is this what you mean, since we can represent E=P/I

Answer 6

so given base power and base impedence
for simplicity , let's think only of real component
\[P_{base}=100 W\]
\[R_{base}=5 \]
From this we can find other base
\[P=V^2/R\]
from this equation , we can find V which is about V_base
P=VI
find I , which is our I_base

so , we only need to define two base variable and define evertying in per unit

Answer 7

@ParthKohli

Answer 8

Next we will tackle generator , which is formula and diagram heavy so I will wait for my tablet to arrive