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Mathematics 20 Online
OpenStudy (anonymous):

How do I find the total area of this prism?

OpenStudy (anonymous):

OpenStudy (anonymous):

@acxbox22 @mathslover can either of you help me with this question?

OpenStudy (acxbox22):

you want the area of the prism or volume?

OpenStudy (anonymous):

The area

OpenStudy (acxbox22):

surface area or lateral surface area?

OpenStudy (anonymous):

Lateral area first then the total area

OpenStudy (anonymous):

The formula for LA is perimeter x height

OpenStudy (acxbox22):

yeah, so first of all use the pythagorean theorum to find the hypotenuse of the triangle base then we cand find perimeter

OpenStudy (anonymous):

\[4^{2} + 6^{2} = x ^{2}\]

OpenStudy (acxbox22):

can you find out the 3rd side side yourself?

OpenStudy (anonymous):

so 16 + 36 = 52 and the \[\sqrt{52} = 2\sqrt{13}\]

OpenStudy (anonymous):

do I add that to the area of the 3 rectangles?

OpenStudy (acxbox22):

no because we need perimeter\[6+4+2\sqrt{13}=10+2\sqrt{13}\]

OpenStudy (anonymous):

So that would be the perimeter?

OpenStudy (anonymous):

Then I multiply that by the height (8)?

OpenStudy (acxbox22):

yes, to get lateral surface area

OpenStudy (anonymous):

So the LA = \[80 + 16\sqrt{13}\]

OpenStudy (acxbox22):

yes good job

OpenStudy (anonymous):

Thank you!!! So from there, how do I find the total area?

OpenStudy (anonymous):

Total Area = LA + 2B

OpenStudy (solomonzelman):

It should be logical to think that there are h (height) number of triangles (the triangles of the surface top) .

OpenStudy (acxbox22):

total surface area just add the area of the 2 bases to the lateral surface area

OpenStudy (anonymous):

So the area of the 2 bases would be the same as the area of the triangle before right? \[2 \sqrt{13}\]

OpenStudy (acxbox22):

2[(6 x 4)/2]+80+16sqrt13

OpenStudy (acxbox22):

no 2sqrt13 was the perimeter not the area

OpenStudy (anonymous):

That would make the h = 8 right? @SolomonZelman

OpenStudy (anonymous):

Oh ok I will work that out

OpenStudy (anonymous):

\[104 + 16\sqrt{13}\]

OpenStudy (anonymous):

@acxbox22 is that right for the TA?

OpenStudy (solomonzelman):

Yes there are many right triangles with legs 4 and 6 (that means that the height and base are these legs). Find the area of this (top surface) triangle, and multiply times height (which is 8).

OpenStudy (anonymous):

@SolomonZelman that would = 96 correct? Which part is this for--total area?

OpenStudy (solomonzelman):

yes you are correct.

OpenStudy (solomonzelman):

\(\normalsize\color{blue}{ ' }\) probably means feet, so just say \(\normalsize\color{blue}{ 96 ft.^{2} }\)

OpenStudy (acxbox22):

and yes @rcschooool you are correct for both parts good job

OpenStudy (acxbox22):

@SolomonZelman 96ft^2 is the volume not the surface area

OpenStudy (solomonzelman):

oh, was the question surface area? Then find the area of each different surface add them together and multiply by 2. You should have 6 surfaces overall.

OpenStudy (anonymous):

Thank you!

OpenStudy (anonymous):

@acxbox22 i have one more total area question, could you explain how to do this one?

OpenStudy (acxbox22):

sure

OpenStudy (anonymous):

Thank you!!

OpenStudy (anonymous):

It gives me the perimeter as 20 already

OpenStudy (acxbox22):

so do you need lateral surface area or total surface area?

OpenStudy (anonymous):

Total area, but do i need to find the lateral area first in order to find the total area?

OpenStudy (anonymous):

Lateral area = 120 right? (I multiplied 20 (perimeter) by 6 (height) @acxbox22

OpenStudy (acxbox22):

yes that is the lateral surface area now we need to find the area of the 2 pentagons to find the total surface area

OpenStudy (acxbox22):

what does that say on the line on the pentagon?

OpenStudy (anonymous):

It says K. I need to find the total area in terms of "k"

OpenStudy (acxbox22):

so it will be 120+(the area of the 2 pentagons in terms of k)

OpenStudy (anonymous):

so \[\frac{ 5 }{ 2 } \times 4 \times k\]

OpenStudy (anonymous):

which equals 10k for the area of one pentagon

OpenStudy (anonymous):

so I would just multiply that by 2? 20k = area of both of the pentagons?

OpenStudy (acxbox22):

yes, i am pretty sure that is correct

OpenStudy (anonymous):

so the TA would be 120 + 20k. thanks for your help!

OpenStudy (acxbox22):

;)

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