Question

Can someone please help me with this question? It is an easy question. I will medal the person with the best answer. Thanks! Also, look at the graph along with the problem.

Find the perimeter of trapezoid KLMN.

104
21
7sqrt{2}+2sqrt{5}+sqrt{26}
2sqrt{26}

I appreciate the help!

Answer 1

@jim_thompson5910

Answer 2

Find the perimeter of trapezoid KLMN.

104
21
\[7\sqrt{2}+2\sqrt{5}+\sqrt{26}\]
\[2\sqrt{26}\]

Answer 3

use the distance formula to find the distance between each point to find the lengths of the sides

then add up the side lengths

Answer 4

What is the distance formula again? I can't remember.

Answer 5

\(\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&({\color{red}{ a}}\quad ,&{\color{blue}{ b}})\quad &({\color{red}{ c}}\quad ,&{\color{blue}{ d}})
\end{array}\qquad
d = \sqrt{({\color{red}{ x_2}}-{\color{red}{ x_1}})^2 + ({\color{blue}{ y_2}}-{\color{blue}{ y_1}})^2}\)

Answer 6

have a look at this page

http://www.mathwarehouse.com/algebra/distance_formula/index.php

Answer 7

Okay. So from LM I got \[\sqrt{50}\]

Answer 8

simplify that to get ???

Answer 9

which equals: 7.071067812

Answer 10

haemm that's correct.. but as jim_thompson5910 may want to simplify it :)

Answer 11

\(\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
L&({\color{red}{ -1}}\quad ,&{\color{blue}{ 6}})\quad M&({\color{red}{ 4}}\quad ,&{\color{blue}{ 1}})\\
M&({\color{red}{ 4}}\quad ,&{\color{blue}{ 1}})\quad N&({\color{red}{ 0}}\quad ,&{\color{blue}{ -1}})\\
N&({\color{red}{ 0}}\quad ,&{\color{blue}{ -1}})\quad K&({\color{red}{ -2}}\quad ,&{\color{blue}{ 1}})\\
K&({\color{red}{ -2}}\quad ,&{\color{blue}{ 1}})\quad L&({\color{red}{ -1}}\quad ,&{\color{blue}{ 6}})\\
\end{array}\qquad
d = \sqrt{({\color{red}{ x_2}}-{\color{red}{ x_1}})^2 + ({\color{blue}{ y_2}}-{\color{blue}{ y_1}})^2}\)

Answer 12

For MN I got \[\sqrt{20}\]

Answer 13

Which equals 4.472135955

Answer 14

I meant

\[\Large \sqrt{50} = \sqrt{25*2}\]
\[\Large \sqrt{50} = \sqrt{25}*\sqrt{2}\]
\[\Large \sqrt{50} = 5*\sqrt{2}\]

Answer 15

do the same for sqrt(20)

Answer 16

that's correct too

Answer 17

So, for KN I got \[\sqrt{8}\]

Answer 18

yeap

Answer 19

simplify that

Answer 20

How do I simplify

Answer 21

I got \[\sqrt{26}\]

Answer 22

for KL

Answer 23

yeap

Answer 24

after you've simplified each one, add them all up

Answer 25

How do I simplify them though? Do I just add the square roots?

Answer 26

did you see my example?

Answer 27

Yes. So it will be: \[7\sqrt{2}+2\sqrt{5}+\sqrt{26}\]

Answer 28

good

Answer 29

I just don't get where the \[7\sqrt{2}\] comes from

Answer 30

what do you get when you simplify sqrt(8)

Answer 31

remember that 8 = 4*2

Answer 32

\(\bf \sqrt{50}\to \sqrt{25\cdot 2}\to \sqrt{5^2\cdot 2}\to {\color{brown}{ 5\sqrt{2}}}
\\ \quad \\
\sqrt{20}\to \sqrt{4\cdot 5}\to \sqrt{2^2\cdot 50}\to {\color{brown}{ 2\sqrt{5}}}
\\ \quad \\
\sqrt{8}\to \sqrt{4\cdot 2}\to \sqrt{2^2\cdot 2}\to {\color{brown}{ 2\sqrt{2}}}
\\ \quad \\
\sqrt{26}\to \sqrt{2\cdot 13}\textit{ 13 is prime so }{\color{brown}{ \sqrt{26}}}\)

Answer 33

ahemm ahem more typos =) \(\bf \sqrt{50}\to \sqrt{25\cdot 2}\to \sqrt{5^2\cdot 2}\to {\color{brown}{ 5\sqrt{2}}}
\\ \quad \\
\sqrt{20}\to \sqrt{4\cdot 5}\to \sqrt{2^2\cdot 5}\to {\color{brown}{ 2\sqrt{5}}}
\\ \quad \\
\sqrt{8}\to \sqrt{4\cdot 2}\to \sqrt{2^2\cdot 2}\to {\color{brown}{ 2\sqrt{2}}}
\\ \quad \\
\sqrt{26}\to \sqrt{2\cdot 13}\textit{ 13 is prime so }{\color{brown}{ \sqrt{26}}}\)

Answer 34

The square root of 8 is 2.828427125

Answer 35

\(\bf 7\sqrt{2}+2\sqrt{5}+\sqrt{26} \checkmark\)

Answer 36

Oh OK. Thanks so much guys!