Question

What is the coordinate of the center of the circle given by the equation (x-3)^2+y^2=15

A. (3,0) B. (-3,0) C. (-3,15) D. (0,3)

Answer 1

\[ (x-3)^2+(y-0)^2=15\]compare to \[ (x-h)^2+(y-k)^2=r^2\]

Answer 2

\(\bf (x-3)^2+y^2=15\implies (x-{\color{blue}{ 3}})^2+(y-{\color{blue}{ 0}})^2=15\qquad {\color{blue}{ center}}\)

Answer 3

(h,k) is the center :)

Answer 4

Thank yall for the help

Answer 5

yw