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Mathematics 31 Online
OpenStudy (jenniferjuice):

1. In order to solve the equation -3x - 6 = 5, the first step is to: add 6 to both sides divide by 5 on both sides subtract 6 from both sides multiply by 5 on both sides 2. Given the equation 3x - 3 = 6x + 1, select the reasoning that correctly solves for x. Add 3, subtract 3x, then divide by -3. Add 3, subtract 6x, then divide by 3. Subtract 1, subtract 3x, then divide by 3. Subtract 1, subtract 6x, then divide by -3. http://assets.openstudy.com/updates/attachments/53a1d2b6e4b04b6404573d26-jenniferjuice-1403137491824-tyu.png

zepdrix (zepdrix):

Hmm so what do you think for the first one? :U

zepdrix (zepdrix):

\[\Large\rm \color{red}{-3x}-6=5\]You want to get the -3x `alone`. Hmm

OpenStudy (jenniferjuice):

so would i add 6 to 5?

zepdrix (zepdrix):

Good. You would have to add 6 to `both sides` to keep things balanced. But yes, add 6 :) good job.

OpenStudy (jenniferjuice):

okay ! could you help me with two more? i could make it a new question so i could give you more medals?

zepdrix (zepdrix):

No it's no big deal. Did you figure out the next one that you posted? \[\Large\rm 3x-3=6x+1\]

OpenStudy (jenniferjuice):

would i add like terms?

zepdrix (zepdrix):

If we look at the first option: ` Add 3`,\[\Large\rm 3x=6x+7\] `subtract 3x`,\[\Large\rm 0=3x+7\]`then divide by -3`,\[\Large\rm 0=-x-2.3\] Hmmm the first option didn't work.

zepdrix (zepdrix):

Well you can't add like-terms since they're on opposite sides of the equality sign. So you'll have to combine them by either subtracting 3x from each side, or by moving the 6x.

zepdrix (zepdrix):

My math was off there, sorry lol 3+1 does not equal 7, it equals 4. But anyway, option 1 still is bad :)

OpenStudy (jenniferjuice):

oh okay but if you 3x from each side there wouldnt be anything on the other side of the equal sign so wouldnt you subract 6x?

zepdrix (zepdrix):

There would still be a 3 wouldn't there?\[\Large\rm 3x-3=6x+1\]Subtracting 3x from each side,\[\Large\rm -3=3x+1\]See there is still stuff on the left side :) We just don't want to add 3 to each side, we want to do something different.

OpenStudy (jenniferjuice):

if i did the second option i would get x-1.333333

OpenStudy (jenniferjuice):

x=1.3333

zepdrix (zepdrix):

Hmmm ok let's try the third option then, \[\Large\rm 3x-3=6x+1\] `Subtract 1,` \[\Large\rm 3x-4=6x\] `subtract 3x,` \[\Large\rm -4=3x\] `then divide by 3,` Does that one work out? :o

OpenStudy (jenniferjuice):

it would be x = -1.3333

zepdrix (zepdrix):

They don't care what the answer is. They want to know which order of procedures gets you to that value :)

zepdrix (zepdrix):

Did the third option lead you to that value without any trouble? :D

OpenStudy (jenniferjuice):

yes :D

zepdrix (zepdrix):

cool c:

zepdrix (zepdrix):

what's next

zepdrix (zepdrix):

Look at Aaron's next step from here, \[\Large\rm -2=2x-6\]See anything wrong with it?

OpenStudy (jenniferjuice):

-2 should have an x ?

zepdrix (zepdrix):

No silly -_- \[\Large\rm -2=2x-6\]If you want all of the `numbers` on the left side, what would be the next step?

zepdrix (zepdrix):

We want to leave our x's on the right. But we want to move the `numbers` to the left. How do we move -6?

OpenStudy (jenniferjuice):

we add 6 to -2 !

OpenStudy (jenniferjuice):

so he made an error when he subtracted 6 ?

OpenStudy (jenniferjuice):

because he was supposed to add 6

zepdrix (zepdrix):

Ah sorry I ran away for a sec >.< Good yes :)

OpenStudy (jenniferjuice):

thanksssss your awesome :DDDD

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