1. In order to solve the equation -3x - 6 = 5, the first step is to: add 6 to both sides divide by 5 on both sides subtract 6 from both sides multiply by 5 on both sides 2. Given the equation 3x - 3 = 6x + 1, select the reasoning that correctly solves for x. Add 3, subtract 3x, then divide by -3. Add 3, subtract 6x, then divide by 3. Subtract 1, subtract 3x, then divide by 3. Subtract 1, subtract 6x, then divide by -3. http://assets.openstudy.com/updates/attachments/53a1d2b6e4b04b6404573d26-jenniferjuice-1403137491824-tyu.png
Hmm so what do you think for the first one? :U
\[\Large\rm \color{red}{-3x}-6=5\]You want to get the -3x `alone`. Hmm
so would i add 6 to 5?
Good. You would have to add 6 to `both sides` to keep things balanced. But yes, add 6 :) good job.
okay ! could you help me with two more? i could make it a new question so i could give you more medals?
No it's no big deal. Did you figure out the next one that you posted? \[\Large\rm 3x-3=6x+1\]
would i add like terms?
If we look at the first option: ` Add 3`,\[\Large\rm 3x=6x+7\] `subtract 3x`,\[\Large\rm 0=3x+7\]`then divide by -3`,\[\Large\rm 0=-x-2.3\] Hmmm the first option didn't work.
Well you can't add like-terms since they're on opposite sides of the equality sign. So you'll have to combine them by either subtracting 3x from each side, or by moving the 6x.
My math was off there, sorry lol 3+1 does not equal 7, it equals 4. But anyway, option 1 still is bad :)
oh okay but if you 3x from each side there wouldnt be anything on the other side of the equal sign so wouldnt you subract 6x?
There would still be a 3 wouldn't there?\[\Large\rm 3x-3=6x+1\]Subtracting 3x from each side,\[\Large\rm -3=3x+1\]See there is still stuff on the left side :) We just don't want to add 3 to each side, we want to do something different.
if i did the second option i would get x-1.333333
x=1.3333
Hmmm ok let's try the third option then, \[\Large\rm 3x-3=6x+1\] `Subtract 1,` \[\Large\rm 3x-4=6x\] `subtract 3x,` \[\Large\rm -4=3x\] `then divide by 3,` Does that one work out? :o
it would be x = -1.3333
They don't care what the answer is. They want to know which order of procedures gets you to that value :)
Did the third option lead you to that value without any trouble? :D
yes :D
cool c:
what's next
Look at Aaron's next step from here, \[\Large\rm -2=2x-6\]See anything wrong with it?
-2 should have an x ?
No silly -_- \[\Large\rm -2=2x-6\]If you want all of the `numbers` on the left side, what would be the next step?
We want to leave our x's on the right. But we want to move the `numbers` to the left. How do we move -6?
we add 6 to -2 !
so he made an error when he subtracted 6 ?
because he was supposed to add 6
Ah sorry I ran away for a sec >.< Good yes :)
thanksssss your awesome :DDDD
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