Question

PLEASE PLEASE THIS IS DUE WITHIN THE HOUR PLEASE HELP!!

The ratio of the areas of two similar polygons is 81:64. If the perimeter of the first polygon is 32 cm, what is the perimeter of the second polygon? Round to the nearest tenth

Answer 1

is the 81 corresponding to the first polygon?

Answer 2

We will need to set up a proportion here.

Answer 3

yeah i guess

Answer 4

Also, Welcome to OpenStudy! :)

Answer 5

okay

Answer 6

thank you

Answer 7

uhm ok

Answer 8

do you try to figure what x is?

Answer 9

because the 32 corresponds with the first polygon which you said was 81, both of those numbers are numerators. You need to find what x, or the corresponding denominator to 64 is for the second polygon.

Answer 10

yes, please find what x is.

Answer 11

i get 25.2839506

Answer 12

OH WAIT OMG SORRY
i didn't read what the question said carefully.
81:64 is for area. not perimeter..

Answer 13

we may have done this wrong..
@KingGeorge I'm not thinking straight, please help?

Answer 14

You nearly got there at the end. Since the 81:64 is a ratio of areas, it won't quite work for the perimeter. But it's still pretty easy. For polygons, the area is a ration of squares. Since \(81=9^2\) and \(64=8^2\), that means that the perimeters should be in a ratio of 9:8 instead.

Answer 15

thank you so much!

Answer 16

who should I give the metal to?

Answer 17

So the actual equation you have to solve is\[\frac{9}{8}=\frac{32}{x}\]Give the medal to whomever you feel like.

Answer 18

THANK YOU!

Answer 19

Give it to Georgie over here

Answer 20

I still appreciate your help to!

Answer 21

I can't leave kc here without a medal either though :P

And you're very welcome sierra

Answer 22

Haha thanks :)
Enjoy your time at OpenStudy Sierra!

Answer 23

will do its very helpful