find the value of tan (-330) degrees
First of all apply this: \[\large{\tan(-x) = -\tan(x)}\]
What will you get ?
I would instead suggest that since tangent is a trig function it's periodic every 360 degrees. that means you can add or subtract 360 to any value and it's the same. tan(x)=tan(x+360) That's another way of looking at it.
tan (x) = tan(x+ 180 deg)
tan is periodic with period pi.
oh it will be \[\tan(-330)= -\frac{ 1 }{ \sqrt{3} }\]
True, but there's no reason to over complicate this @primeralph .
It's not getting over-complicated.
Yeah, I guess you're right. Alright, well @goformit100 are you working on it or still stuck?
He's offline
will the answer have -ve sign or +ve sign ?
Tan is odd function so, tan(-330)=-tan(330)=- tan(90*3+60) (90*3+60) indicates 4th quadrant. in which tan theta is negative. so answer is negative. also multiple of 90 is odd, so tan changes to cot theta. so - tan(330)=-(-cot 60)=cot 60
@Koikkara
tan(-330)=-tan(330) How ?
because tan theta is odd function. and odd function means f(-x)=-f(x)
I just realized @primeralph 's picture isn't a lava monster or some sort of Tron character. Lol wtf.
also, \[\tan \Theta=\frac{ \sin \Theta }{ cos \Theta }\] sin is odd function and cos is even. so tan is also odd fxn.
Will the answer be |dw:1403154923058:dw|
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