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How do I factor this fourth degree polynomial, x^3+9x^2-9x-81?
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take x^2 in common among x^3+9x^2 and -9in common among -9x-81
Actually this is a third degree polynomial.
x^2(x+9)-9(x+9)
yeah u r correct
cool thanks
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proceed further
I don't know what to do next
@Kainui whatever
take (x+9) common...
x^2-9(x+9)^2
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not sure what to do here
x^2(x+9)-9(x+9) = (x+9) (x^2 - 9)
oh ok
and that's it right?
yup
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thank you
it was wrong
@MikeB55 it cant be wrong man....solve (x + 9)*(x^2 - 9)
Just the form they wanted was off I guess. It was (x+9)(x+3)(x+3)
oh yeah..and its (x+3)(x-3)(x+9)
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