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Help please!? How do I solve and get the answer for this question? The temperature of a sample of argon gas in a 365 ml container at 740. MmHg and 25degree celcius is lowered to 12C. Assuming the volume of the container and the amount of gas is unchanged, calculate the new pressure of argon. A. 0.468 atm B. 0.931 atm C. 1.02 atm D. 1.54 atm E. 2.03 atm
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\[V1P1/T1=V2P2/T2\] basically just plug and chug
any further questions or did this not make sense?
Thank you! It was just what I needed.
glad to help :)
wish i could've got that medal though
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