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OpenStudy (anonymous):

a truck with mass of 2000 kg speeding at 36 km/hour crash into a tree and stopped in 0.1 second. The average force exerted on the truck during the crash is A. 200N B. 2000N C. 20000N D. 200000N E. 2000000N

OpenStudy (anonymous):

Convert the velocity to m/s. Then equate impulse with change in momentum to find the average force. \[\color{green}{\vec{F} \Delta t = m \Delta \vec{v}}\]

OpenStudy (anonymous):

do you mean the 36km/hour

OpenStudy (anonymous):

Yes. Convert it into m/s.

OpenStudy (abhisar):

Hello @dinisha !

OpenStudy (abhisar):

36 km/hr = 10m/s

OpenStudy (abhisar):

by using v=u+at, we can calculate the accelaration a

OpenStudy (abhisar):

here, v=0 u=10m/s & t=0.1sec

OpenStudy (abhisar):

now using F=ma we can calculate the force, here m=2000kg

OpenStudy (abhisar):

Hope it helped

OpenStudy (anonymous):

yaa really alot @Abhisar .. the answer will be D 200000N

OpenStudy (anonymous):

NIce. Both methods will work. Abishar's is a bit easier to follow.

OpenStudy (abhisar):

\(\Huge\text{Anytime !}\) \(\huge\ddot\smile\)

OpenStudy (anonymous):

Oops ... sorry I misspelled your handle Abhisar.

OpenStudy (abhisar):

it's all ryt @ghuczek !

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