a truck with mass of 2000 kg speeding at 36 km/hour crash into a tree and stopped in 0.1 second. The average force exerted on the truck during the crash is
A. 200N
B. 2000N
C. 20000N
D. 200000N
E. 2000000N
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Convert the velocity to m/s. Then equate impulse with change in momentum to find the average force.
\[\color{green}{\vec{F} \Delta t = m \Delta \vec{v}}\]
OpenStudy (anonymous):
do you mean the 36km/hour
OpenStudy (anonymous):
Yes. Convert it into m/s.
OpenStudy (abhisar):
Hello @dinisha !
OpenStudy (abhisar):
36 km/hr = 10m/s
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (abhisar):
by using v=u+at, we can calculate the accelaration a
OpenStudy (abhisar):
here, v=0
u=10m/s & t=0.1sec
OpenStudy (abhisar):
now using F=ma we can calculate the force,
here m=2000kg
OpenStudy (abhisar):
Hope it helped
OpenStudy (anonymous):
yaa really alot @Abhisar .. the answer will be D 200000N
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
NIce. Both methods will work. Abishar's is a bit easier to follow.