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Mathematics 8 Online
OpenStudy (anonymous):

Find the value of b.

OpenStudy (anonymous):

OpenStudy (anonymous):

9.8 17.9 4.1 96.2

OpenStudy (mathstudent55):

Law of Cosines

OpenStudy (anonymous):

I'm completely lost

OpenStudy (mathstudent55):

Have you heard of the law of cosines? It's what you need to use to find \(b\).

OpenStudy (anonymous):

a2 = b2 + c2 – 2bc cos A ?

OpenStudy (anonymous):

like idk how to put it into an equation. very confusing

OpenStudy (mathstudent55):

Yes. You need to use the form of the law of cosines that will give you \(b\).

OpenStudy (mathstudent55):

Look at what you have: \(a\), \(c\), and \(B\). You are looking for \(b\).

OpenStudy (anonymous):

so a2 = b2 + 15^2 -0.91

OpenStudy (mathstudent55):

You have \(\rm \color{red}{these}.\) You are looking for \(\rm\color{blue}{this}.\) \(\color{blue}{b}^2 = \color{red}{a}^2 + \color{red}{c}^2 -2\color{red}{ac} \cos \color{red}{B}\)

OpenStudy (anonymous):

idk lol

OpenStudy (anonymous):

ohh

OpenStudy (mathstudent55):

\(\color{blue}{b}^2 = \color{red}{9}^2 + \color{red}{15}^2 -2 \cdot\color{red}{9 \cdot 15} \cdot \cos \color{red}{39^o}\)

OpenStudy (mathstudent55):

Calculate the right side to find \(b^2\), then take the square root to find \(b\).

OpenStudy (anonymous):

so its 9 ?

OpenStudy (mathstudent55):

Did you get just 9, or 9 point something?

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