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OpenStudy (anonymous):
What is the solution of log3 x − 5 16 = 2?
x = −4
x = 4
x = −3
x = 3
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OpenStudy (anonymous):
@ganeshie8
OpenStudy (dan815):
should that say 5^16 or something
ganeshie8 (ganeshie8):
yeah looks like it got messed up while copy past
ganeshie8 (ganeshie8):
\(\large \log_{3x-5} ~16 = 2\)
like this @gabylovesu ?
OpenStudy (dan815):
ahh that makes sense
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OpenStudy (anonymous):
I guess.
ganeshie8 (ganeshie8):
start by changing it to exponent form, use below :
\(\large \log_a b = c \) can be written in exponent form as \(\large b = a^c\)
ganeshie8 (ganeshie8):
\(\large \large \log_{3x-5} ~16 = 2\) can be written as \(\large 16 = (3x-5)^2\)
ganeshie8 (ganeshie8):
Notice that 16 is a special number - any guess why is it special ?
OpenStudy (dan815):
you there gaby?
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OpenStudy (anonymous):
Yeah I am it is just that my computer is acting up.
OpenStudy (anonymous):
Um I am not sure why the 16 is a special number. @ganeshie8
ganeshie8 (ganeshie8):
Okay, 16 is a perfect square :
16 = 4^2
ganeshie8 (ganeshie8):
\(\large 4^2 = (3x-5)^2\)
ganeshie8 (ganeshie8):
since the exponents are equal, we can compare the bases :
\(\large 4 = 3x - 5\)
solve \(\large x\)
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