What is the solution of log3 x − 5 16 = 2? x = −4 x = 4 x = −3 x = 3
@ganeshie8
should that say 5^16 or something
yeah looks like it got messed up while copy past
\(\large \log_{3x-5} ~16 = 2\) like this @gabylovesu ?
ahh that makes sense
I guess.
start by changing it to exponent form, use below : \(\large \log_a b = c \) can be written in exponent form as \(\large b = a^c\)
\(\large \large \log_{3x-5} ~16 = 2\) can be written as \(\large 16 = (3x-5)^2\)
Notice that 16 is a special number - any guess why is it special ?
you there gaby?
Yeah I am it is just that my computer is acting up.
Um I am not sure why the 16 is a special number. @ganeshie8
Okay, 16 is a perfect square : 16 = 4^2
\(\large 4^2 = (3x-5)^2\)
since the exponents are equal, we can compare the bases : \(\large 4 = 3x - 5\) solve \(\large x\)
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