John deposited $2860 in a bank that pays 9% interest, compounded monthly. Find the amount he will have at the end of 3 years.

Question

jdoe0001 · Answer

$\bf A=P\left(1+\frac{r}{n}\right)^{nt}
\ \quad \
A=\textit{current amount}\
P=\textit{original amount deposited}\to \$2,860\
r=rate\to 9\%\to \frac{9}{100}\to 0.09\
n=\textit{compounding cycle, monthly, means 12 times per year}\to 12\
t=years\to 3
\ \quad \
A=2,860\left(1+\frac{0.09}{12}\right)^{12\cdot 3}$