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If v = <5, -4>, find ||v||. 1 29√ 41√ 21√
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\[\Large ||<a,b>|| = \sqrt{a^2+b^2}\]
Can you apply the formula I gave you above here? @davidza6496
i just plug 5 into A^2 and -4 into B^2
5 into a and -4 into b
so what do you get?
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i got 3?
did you plug in correctly? after plug in, it should looks like this: \[\Large \sqrt{(5)^2+(-4)^2}\]
yeah i did it again and got 3
@geerky42
\[\Large\rm \vec v=\left<\color{orangered}{5},\color{royalblue}{-4}\right>\] \[\Large\rm ||v||=\sqrt{\color{orangered}{5}^2+(\color{royalblue}{-4})^2}\]\[\Large\rm ||v||=\sqrt{25+16}\]Did you remember to square the negative sign?
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ohh ok i did it wrong, but i got it now thank you!
Cool :)
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