Question

how do i simplify
(8+√5)(8-√5)
64-8√5+8√5-√25

Answer 1

this is a difference of squares so your middle term will cancel out

Answer 2

\[8^2-\sqrt{5}^2\]

Answer 3

64-5

Answer 4

for the 1st one, keep in mind as precal said \(\bf \large (a-b)(a+b) = a^2-b^2\)

Answer 5

59 is the solution

Answer 6

look for these, these are the easy ones to do.....

Answer 7

so it would be 59 because \[64-\sqrt{25}\] \[64-5=59\]

Answer 8

yeap

Answer 9

what happened to the radical 25 @linb

Answer 10

\(\bf 64\cancel{ -8\sqrt{5} }\cancel{ +8\sqrt{5} }-\sqrt{25}
\\ \quad \\
64-\sqrt{5^2}\implies 64-5\implies 59\)

Answer 11

\(\bf \large \sqrt[{\color{red}{ 2}}]{5^{\color{red}{ 2}}}\iff 5\)

Answer 12

ohhh

Answer 13

good job jdoe001

Answer 14

thanks guys

Answer 15

anytime.....

Answer 16

np