Question

I am to solve the exponential equation of 5^(x+3)=242 in natural logarithms.
I have so far for the solution set x+3= ln 242/ln 5
I need help better understanding how to do this and on how to use a calculator to give the decimal approximation for the set. Which I have as:
.41046876288

How does this look?

Answer 1

do you want to know how to set the calculator upto some decimal points...?

Answer 2

I think I have figured that out and now I am trying to see if my solutions are correct. :-)

Answer 3

Meaning if it is correct I figured it out. :-D

Answer 4

i don't understand what you want to know...?

Answer 5

If I have the right logarithm solution set and the right decimal approximation of x in the equation.

Answer 6

x+3=3.41046876288
x=.41046876288
yeah, definitely,it's correct.

Answer 7

Thanks. :-)
Do you know how to properly express the solution set?
Because I am unsure.
I think it is to be \[x+3=\frac{ \ln 242 }{ \ln 5 }\]

Answer 8

this property you can use to find the value of log in any base.
\[\ln _{5}242=\frac{ \ln 242 }{ \ln 5 }\]

Answer 9

Thanks. :-D

Answer 10

any time... @ShortStaticBurst ...:)