If A and B are two acute angles satisfying the equation 3sin^2A + 2sin^2B=1 and 3sin2A-2sin2B=0 then A+2B
Welcome to OpenStudy Pajji
Sir Please Show your working.
I'll attach a file wait for once I have converted sorry I can't attch the file but I will till you the steps till where I reached 3sin^2A=1- 2sin^2B (1-2sin^2B=cos2b 3sin2A=2sin2b cancelling sin on both sides(I think this method is wrong) then getting 3A=2B then equating it in the above equation
Now what to do???????????? big question
Sir pls help
three anwers are given in the textbook for this question 14 ,15 and 17
it's ok. Now solve and Show this question too in the same way :- 3sin2A-2sin2B=0
can I cancel sin on both sides?
or should I use double angle property
not cancel only you can remove sine both sides
@ParthKohli HELP BRO I got stuck in this question
@patrickthestar
pls help @ParthKohli sir
with?
I am not able to solve this problem I am trying it for last 1 hr pls any1 help because day after tomorrow is my exam
@patrickthestar have u to any step pls hare I will try to solve it from there
hare=share
Hey, I think I found the value for 2a+2b..but that doesn't solve your purpose..does it?
pls share it
It's around 110 degree..what is the answer?
@kanwal32 not many people are on who can answer these type of questions. I'm sorry but you may have to wait till tomorrow to have this question answered. @Hero @Luigi0210 Help if you can guys :)
90 is degree
Let me check that again!
I am getting 2a+2b=107.45 degree!
@dan815 will be better help :)
@dan815 @dan815 @dan815 We call upon thy booty @dan815 @dan815 @dan815 @dan815
@dan815 pls help
hey okay
pls save my life @dan815
thnx
sorry i believe i mis read your question the square is only for the first equations right
yes
can we conver 1-2sin^2(b) =cos2b
3sin^2A + 2sin^2B=1 <--- use this identitiy sin^2(A)=1/2(1-cos(2a)) 3sin2A-2sin2B=0
Yes and then derive the first line and then you will have it in terms of sin
Then you can use a linear combination to eliminate
3/2-3/2cos(2a)+1-cos2b=1 deriving this gives 3sin2a+2sin2b=0 other eqn 3sin2A-2sin2B=0 How we can add them together and eliminate 2sin2b and solve for A, remember A<pi/2 rad or <90 deg
Any questions?
no thnx
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