the population of a region is 100,000. there are 250 albinos in the region . the estimated number of normal person carryiing albino gene is : A. 5900 B. 9500 C. 95000 D.59000 E. 159000
@Abhisar
Hello @hemarubenY !
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Which do you think it is? Why or why not? It would be easier to tutor you if you explained what about the question is giving you trouble.
In order to make u understand this i'll work out an other example related to this question !
\(\bf Formulas~Used\) \(\bullet\) P+Q =1 \(\bullet\) and \[P ^{2}+2PQ+Q ^{2}=1\]
Here, P=frequency of A Q=frequency of a 2PQ = frequency of Aa
Now let's see an example \(\color{red}{\text{In a random population frequency of recessive phenotype is 0.09.}}\)\(\color{red}{\text{What is the frequency of heterozygous genotype ?}}\)
\(\huge\color{blue}{\text{Solution}}\) Let the recessive allele be a and dominant trait be A. Now frequency of a recessive phenotype = 0.09 i.e frequency of aa = 0.09.
This implies that frequency of a = \(\sqrt{0.09}\) = 0.03 Now using the formula P+Q = 1, we get that frequency of A = 1-0.03 = 0.7
Frequency of heterozygote i.e Aa = 2PQ = 2*0.7*0.03 = 0.42
This means in a population of 100 individuals, 42 will have a genotype of Aa
You can workout ur question in same manner. Just remember that Albinism is a recessive disease. They have given uh the frequency of aa and wants u to calculate Aa
You can workout ur question in same manner. Just remember that Albinism is a recessive disease. They have given u the number of aa so and wants u to calculate number of Aa. Frequency of aa will be 250/100000.
Hope it helps ! \(\color{green}{\huge\ddot\smile}\)
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