I have this trig question:
If sec (theta) = -2 with and cos (theta) 0. Find the six trigonometric functions of (theta)

X=?
Y=?
r=?

Sin (theta) = y/r

Question

I have this trig question:
If sec (theta) = -2 with and cos (theta) > 0. Find the six trigonometric functions of (theta)

X=?
Y=?
r=?

Sin (theta) = y/r

anonymous · Answer

csc (theta) = r/y
cos (theta) = x/r
Sec (theta) = r/x
tan (theta) = y/x
cot (theta) = x/y

But I'm guessing that r=2 and x=-1 but I'm not sure

anonymous · Answer

I just have a problem what is X,Y and r. It's okay not to answer the 6 functions

anonymous · Answer

$\sec\theta=\dfrac{1}{\cos\theta}=-2$, or $\cos\theta=-\dfrac{1}{2}$.

$\cos\theta=\dfrac{x}{r}$, and since $r$ is always positive, you have $x=-1$ and $r=2$.

From this you can extract the value of $y$, since $x^2+y^2=r^2$. You'll then have all the info need to find the trig ratios.

The information you're given, that $\cos\theta>0$, doesn't make sense, since the cosine is clearly negative.