Walk me through it
How many grams of zinc metal will react completely with 5.4 liters of 2.8 M HCl? Show all of the work needed to solve this problem.
Zn (s) + 2 HCl (aq) ---> ZnCl2 (aq) + H2 (g)
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No I wanted to wait for you haha you make it make sense
OpenStudy (chmvijay):
would you like to walk with me through this ?
OpenStudy (anonymous):
Sure
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OpenStudy (chmvijay):
ok from equation can u tell me how many mole of Zn reacts with how many moles of HCl?
OpenStudy (anonymous):
2.8 moles of HCI right?
OpenStudy (chmvijay):
where does 2.8 come from? i didnt find it from the equation
OpenStudy (somy):
oh
OpenStudy (anonymous):
"How many grams of zinc metal will react completely with 5.4 liters of 2.8 M HCl?"
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OpenStudy (chmvijay):
ok @Somy came better she know how well she can make u unserstnd s this :P
OpenStudy (anonymous):
Okay thank you!
OpenStudy (chmvijay):
bbye
OpenStudy (somy):
lol where are we?
OpenStudy (anonymous):
Well all I know is that there are 2.8 moles of HCI
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OpenStudy (somy):
how did u get it?
OpenStudy (anonymous):
I literally says it in the equation
OpenStudy (anonymous):
"How many grams of zinc metal will react completely with 5.4 liters of 2.8 M HCl?"
OpenStudy (somy):
How many grams of zinc metal will react completely with 5.4 liters of 2.8 M HCl? Show all of the work needed to solve this problem.
Zn (s) + 2 HCl (aq) ---> ZnCl2 (aq) + H2 (g)
OpenStudy (somy):
2.8 M
M is molarity, thus its CONCENTRATION not mole
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OpenStudy (anonymous):
Ohhhh
OpenStudy (somy):
yeah so for HCl
you are given molarity = 2.8 M
and volume = 5.4 L
OpenStudy (somy):
Molarity and concentration are same things thus units are same
volume we always convert it to dm3 right? you are given in Liters
Liters is equal to dm3 so these two are also same thing
OpenStudy (somy):
get it?
OpenStudy (anonymous):
Okay so if it's already in Liters I don't have to touch it
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OpenStudy (somy):
yes exactly :)
OpenStudy (somy):
what is the formula of molarity?
OpenStudy (anonymous):
M = moles solute/liters solution
OpenStudy (somy):
yup so you need to find mole right?
OpenStudy (anonymous):
Yeah
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OpenStudy (somy):
good so find it now
OpenStudy (anonymous):
2.8/5.4 = 0.51
OpenStudy (somy):
wrong
OpenStudy (somy):
hmmm u still have problems with making subjects in formulas
OpenStudy (somy):
i think we should have a small tutorial on this later
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OpenStudy (anonymous):
Okay
OpenStudy (somy):
conc= mole/dm3
if you make mole as subject that will be mole= conc*dm3
OpenStudy (anonymous):
Okay 2.8*5.4 = 15.12
OpenStudy (somy):
yup that's right
OpenStudy (somy):
Zn (s) + 2 HCl (aq) ---> ZnCl2 (aq) + H2 (g)
okay so mole of 2HCl is 15.12moles
what is mole of Zn?
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OpenStudy (somy):
look at the ratio between HCl and Zn
in reaction its 1:2 right?
OpenStudy (anonymous):
I hate ratios but I see that
OpenStudy (somy):
yeah so if
2 -> 15.12 mole
1 -> X
OpenStudy (anonymous):
7.56!
OpenStudy (somy):
bingo :)
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OpenStudy (somy):
so Zn= 7.56 mole
OpenStudy (somy):
now tell me what is mole formula?
OpenStudy (anonymous):
n = m/M
OpenStudy (somy):
yup and u need to find mass right?
OpenStudy (somy):
u know Mr of Zn from periodic table and u already calculated mole
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OpenStudy (anonymous):
Whats the formula for that?
OpenStudy (somy):
molecular mass
OpenStudy (somy):
formula for what?
OpenStudy (anonymous):
wait all I have to do is look of the molecular mass of Zn right
OpenStudy (anonymous):
which is 65.
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OpenStudy (anonymous):
n = m/M
n = 65/ 7. 56
= 8. 59
OpenStudy (somy):
noo
OpenStudy (somy):
mole= mass/ Mr
OpenStudy (somy):
so mass = mole*Mr
OpenStudy (anonymous):
7.56*65 = 491. 4
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OpenStudy (somy):
yup
OpenStudy (anonymous):
Now we do mole = mole/Mr?
OpenStudy (somy):
no lol we are done :)
OpenStudy (somy):
you got the mass of zinc they asked you for :)
OpenStudy (anonymous):
Thank you:)
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OpenStudy (somy):
you are welcome :) i'll open a new question where i'll teach you how to work with formulas ok?