Question

The sum of 6 and twice a number is multiplied by three. This product is greater than or equal to 66. What is the smallest value possible for this number?

Answer 1

"First solve the inequality for x.
The sum of 6 and twice a number (the unknown, represented by the variable x) multiplied by 3 translates to this expression algebraically: 3(2x + 6).
This product is greater than or equal to 66.
Expand the multiplication to: 6x + 18, which is greater than or equal to 66.
Then subtract 18 from both sides to get: 6x is greater than or equal to 48.
Then divide both sides by 6 to get: x is greater than or equal to 8.
If x is greater than or equal to 8, then x could be 8 or 9 or 10, etc., any number from 8 on up into infinity! The smallest possible value for x given these constraints is 8.

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Answer 2

First let the number=x. So the sum of 6 and twice a number multiplied by 3 will look like this:
3*(2x+6). Then the problem says that this number is greater than or equal to 66, so your equation should look like this:
3*(2x+6) \[\ge \]66.

Proceed to solve