In the reaction MgCl2 + 2KOH Mg(OH)2 + 2KCl, how many moles of Mg(OH)2 are produced for every mole of MgCl2?
A. 3
B. 1
C. 2
D. 1/2

Question

In the reaction MgCl2 + 2KOH Mg(OH)2 + 2KCl, how many moles of Mg(OH)2 are produced for every mole of MgCl2?
                A. 	3
  		B. 	1
  		C. 	2
  		D. 	1/2

anonymous · Answer

Since the equation is balanced, we can go ahead and look at the coefficients of each compound to see how many moles of each are used and produced in a reaction.

Since there is 1 mole of MgCl2 used in the reaction, how many moles of Mg(OH)2 are produced? (Hint: look at the coefficient)

zab505 · Answer

2? so answer is c?

anonymous · Answer

The coefficient of Mg(OH)2 is 1, right?

zab505 · Answer

Yeah

anonymous · Answer

So for every 1 mole of MgCl2 consumed, there is 1 mole of Mg(OH)2 produced. Make sense?

anonymous · Answer

The coefficients of the reactants and products represent the molar ratios between them all.

zab505 · Answer

Ah I see. Thank you so much!

anonymous · Answer

No problem!