Question

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Identify whether the series summation of 12 open parentheses 3 over 5 close parentheses to the I minus 1 power from 1 to infinity is a convergent or divergent geometric series and find the sum, if possible.

This is a convergent geometric series. The sum cannot be found.

This is a convergent geometric series. The sum is 30.

This is a divergent geometric series. The sum cannot be found.

This is a divergent geometric series. The sum is 30.

Answer 1

Convergent geometric series, the sum is 30.

Answer 2

if its right ill medal you! (:

Answer 3

And 1 more question can you help me?

Answer 4

Identify whether the series summation of 15 open parentheses 4 close parentheses to the I minus 1 power from 1 to infinity is a convergent or divergent geometric series and find the sum, if possible.

This is a convergent geometric series. The sum is –5.

This is a divergent geometric series. The sum is –5.

This is a convergent geometric series. The sum cannot be found.

This is a divergent geometric series. The sum cannot be found.

Answer 5

r = 3/5 which is less than 1, so the series will converge. To find the sum, you just need to use the geometric formula:

where a1 is the first term in the series and r is the fraction being multiplied.

Answer 6

That is a divergent series, the sum cannot be found. r = 4 which is greater than 1, so it will keep getting bigger and bigger as it goes until infinity.

Answer 7

OMG THANK YOU SOO MUCH!!!! (:

Answer 8

No problem!