Prove the Converse of the Pythagorean Theorem. The Converse of the Pythagorean Theorem states that when the sum of the squares of the lengths of the legs of the triangle equals the squared length of the hypotenuse, the triangle is a right triangle. Be sure to create and name the appropriate geometric figures.
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@mathstudent55 can u plz help me!!!
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EF = BC = a ÐF is a right angle. FD = CA = b triangle EF = BC = a angle F is a right angle. FD = CA = b In triangle DEF, By Pythagoras Theorem, a2 + b2 = c2 the given AB=c= a^2 + b^2 square root Theorefore AB = DE But by construction, BC = EF and CA = FD triangle ABC congruent to DEF (S.S.S.) Do you get this?
what is a?
I'm confused
Ok let me think of another way to write it...
what do a and b stand for?
The legs of the triangle... C is the hypotenuse..
oh ok can u go on
what r ef and bc
@mathstudent55 can u plz help me?
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Given: Triangle ABC with \(a^2 + b^2 = c^2\) Prove: Triangle ABC is a right triangle
can i use that?
Yes. This is the proof of the converse of the Pythagorean theorem.
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ok i also need help because I'm not that good with proving i don't understand what u have to put for statements and justifications
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