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What volume of 0.10 M NaOH is required to neutralize 30 mL of 0.10 M HCl? Does anybody know a formula that would help me find this?
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@Destinymasha @dan815
First you have to set up the equation: \[NaOH + HCl \rightarrow H_2O + NaCl\]
And then you just have to do a bunch of conversions: \[30 mL(\frac{ 1L }{ 1000mL })(\frac{ 0.1molHCl }{ 1L })(\frac{ 1 mol NaOH }{ 1 mol HCl })(\frac{ 1L }{ 0.1molNaOH })(\frac{ 1000mL }{ 1L })\]
Thanks! so the answer would be 30 mL?
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