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Mathematics 19 Online
OpenStudy (anonymous):

HELP!!! METAL/FAN !!!! FLVS ALG.2 lesson 08.04 Geometric Series Please comment if you think you can help me! (:

OpenStudy (anonymous):

I can help out

OpenStudy (anonymous):

do you do flvs?

OpenStudy (anonymous):

I used to in high school

OpenStudy (anonymous):

oh sweet! okay hold on.

OpenStudy (marissalovescats):

Look at all of us FLVSers :P

OpenStudy (anonymous):

That Is the Way the Ball Bounces! Sam completed the following procedure in his Algebra II class: Choose a height from which all of the balls will be dropped one at a time. Vertically along the blank wall, set up the measuring tape and step stool or chair. Have a family member or friend stand on a step stool and drop one of the balls from the chosen height. Drop the ball close enough to the measuring tape to be able to record height, but not touch the tape. Face the measuring tape, opposite the ball's starting point from about 7 or 8 feet high. As the ball falls, measure the height the ball reaches after each bounce for four consecutive bounces. (You may need to repeat the process to ensure that your measurements are accurate. You may choose to video each drop to assure accuracy.) illustration showing a ball bouncing 4 times if someone dropped the ball from 7 or 8 feet high He recorded the height of each bounce, beginning with the height from which the ball originally fell, in the chart below: Ball 1 Description Ball 2 Description Ball 3 Description Height 1 (starting point) 3 ft 3 ft 3 ft Height 2 2.4 1.9 0.9 Height 3 1.9 1.2 0.3 Height 4 1.5 0.8 0.1 Height 5 1.2 0.5 0.02 Using complete sentences, answer the following questions: What is the average common ratio between the successive height values of ball 1? Ball 2? Ball 3? Experimental errors may cause common ratios to have some variances within the data for one ball. Use the average common ratio. What is the height of each ball on the fifth bounce (i.e., Height 6)? Use the geometric sequence formula, an = a1rn – 1 and show your work. What is the total distance of the height each ball has traveled in the first five heights? Use the geometric series formula, Sn = the quantity of a sub 1 minus a sub 1 times r to the n power, all over 1 minus r and show your work.

OpenStudy (anonymous):

i just copied and pastede idk how else to make it... @marissalovescats did you do this one? i cant figure it out!!

OpenStudy (marissalovescats):

No I didn't take Algebra 2 on FLVS and I'm not sure what they want you to do I'd have to take a second and really read it to see if I can help haha one sec

OpenStudy (anonymous):

okay thats fine! (:

OpenStudy (marissalovescats):

I don't see how you can answer their question if they don't have the descriptions for ball 2 and 3

OpenStudy (anonymous):

Ball 1 Description Ball 2 Description Ball 3 Description Height 1 3 ft 3 ft 3 ft (starting point) Height 2 2.4 1.9 0.9 Height 3 1.9 1.2 0.3 Height 4 1.5 0.8 0.1 Height 5 1.2 0.5 0.02

OpenStudy (anonymous):

there is the graph! @marissalovescats

OpenStudy (anonymous):

height 2 ball 3 is 0.9...

OpenStudy (marissalovescats):

Oh okay so for the first part it wants average common ratio so I'm thinking you find how each height is decreasing. So for Height 1 we have 3, 3 and 3 so the average ratio would be 0 because it's staying at a consistent height. For Height 2 we have 2.4, 1.9, 0.9 so it goes down 0.5 at first and then it goes down 1 whole inch so I'm guessing the average ratio for that would be like Ball 1 - 0.5n where n is the number of the bounce or each ball they drop. So the second ball you'd use 2 for n the 3rd ball you'd use 3 for n... Does that make sense?

OpenStudy (marissalovescats):

For Height 3 we have 1.9, 1.2, 0.3 it goes down 0.7 the first time and then the second time it goes down 0.9 so in this one each time the ball drops, it drops 0.2 points more than the last time. Height 4 we have 1.5, 0.8, 0.1 so it goes down 0.7 the first time and then 0.7 again the second. So it will continually drop 0.7 less each time Height 5 we have 1.2, 0.5, 0.02 goes down first at 0.7 and then once again goes down 0.48 so I'm not sure about that one lol

OpenStudy (anonymous):

Thank you.

OpenStudy (anonymous):

flvs is gay

OpenStudy (anonymous):

I still need part 2 and 3 and yes.. i agree!!

OpenStudy (anonymous):

think u could help me though? @1800_RATCHETHUNTERS

OpenStudy (anonymous):

i'll try

OpenStudy (anonymous):

okay can u look at part 2 and 3?

OpenStudy (anonymous):

sure

OpenStudy (anonymous):

ya i'm not sure @kemist @ParthKohli

OpenStudy (anonymous):

alright... thanks anyways!

OpenStudy (anonymous):

ya well love him more now

OpenStudy (anonymous):

lol what?

OpenStudy (anonymous):

nvm

OpenStudy (anonymous):

i know what u meant...

OpenStudy (anonymous):

okay good

OpenStudy (anonymous):

@Javonthecoolman canu u help?

OpenStudy (anonymous):

Yes I can help

OpenStudy (anonymous):

What is the height of each ball on the fifth bounce (i.e., Height 6)? Use the geometric sequence formula, an = a1rn – 1 and show your work. What is the total distance of the height each ball has traveled in the first five heights? Use the geometric series formula, Sn = the quantity of a sub 1 minus a sub 1 times r to the n power, all over 1 minus r and show your work. with the table i made...

OpenStudy (anonymous):

Add count divide and multiply .

OpenStudy (anonymous):

wanna answser them for me?

OpenStudy (anonymous):

Sure honey

OpenStudy (anonymous):

1 minus a sub 1 times r to the n power, all over 1 minus r

OpenStudy (anonymous):

Then an = a1rn – 1 + 2

OpenStudy (anonymous):

fifth bounce (i.e., Height 6)

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