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object is moving in space according to s(t)=(t^4)-t where t is in seconds and s(t) is in feet. find the instaneous velocity at t = 2 feet.
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it is called derivative
what do you mean ?
velocity is derivative of position function they gave you
The instantaneous velocity at \(t=2\) feet is the derivative (rate of change) of \(s(t)\) when \(t=2\). Basically, find the derivative \(s'(t)\) and plug in \(t=2\) to find \(s'(2)\).
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