Question

What are the approximate solutions of 4x^2 + 2x = 17, rounded to the nearest hundredth?

x ≈ -2.33 and x ≈ 1.83

x ≈ -1.83 and x ≈ 2.33

x ≈ -9.31 and x ≈ 7.31

No real solutions

Answer 1

have you covered the quadratic formula yet?

Answer 2

no lol

Answer 3

hmm ok
so... have you covered quadratic equations yet?

Answer 4

some what but im not to good with it

Answer 5

well... ok... the quadratic formula is quite simple

\(\bf 4x^2 + 2x = 17\implies 4x^2 + 2x-17=0
\\ \quad \\

\textit{quadratic formula}\\
y={\color{blue}{ 4}}x^2{\color{red}{ +2}}x{\color{green}{ -17}}
\qquad \qquad
x= \cfrac{ - {\color{red}{ b}} \pm \sqrt { {\color{red}{ b}}^2 -4{\color{blue}{ a}}{\color{green}{ c}}}}{2{\color{blue}{ a}}}\)

Answer 6

for more info, when you have time, see
http://www.khanacademy.org/math/algebra/quadratics/quadratic-formula/v/using-the-quadratic-formula

Answer 7

so colorful..

Answer 8

or use completing square:
\[4x^2 + 2x = 17\]
\[x^2 + x/2 = 17/4\]
\[(x+1/4)^2 = 17/4+1/16\]
so approximate solution is
\[-\frac{1}{4}\pm 2\]