Question

Indicate the number of unpaired electrons for following: [noble gas]ns2(n−1)d2

Answer 1

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Answer 2

Let us take n=4

Answer 3

Then the electronic configuration will be
\[1s ^{2}2s ^{2}2p ^{6}3s ^{2}3p ^{6}4s ^{2}3d ^{2}\]

Answer 4

So, there are 2 unpaired electrons in 3d orbital.