Question

Is it possible to get an undefined answer in a limit?

Answer 1

the limit does not always exist

Answer 2

for many different reasons

Answer 3

if you mean, in the case where you would potentially divide by zero when approaching it; no

Answer 4

the numerator is non zero while the denominator is 0

Answer 5

is it the same if I answer the limit does not exist or I'd just write undefined?

Answer 6

i think they are two separate terms. do you have an example of a problem so we can classify it?

Answer 7

I'd say, "If a limit is undefined, then it does not exist," but that's me

Answer 8

\[\lim_{t \rightarrow 0} 1/t - (1/t^2+t)\]

Answer 9

I got 1/ 0 I'm just not sure with my answer

Answer 10

\[\lim_{t\to0}\left(\frac{1}{t}-\frac{1}{t^2}-t\right)~~?\]

Answer 11

\[\lim_{t \rightarrow 0} \ \frac{ 1 }{ t } - \frac{ 1 }{ t^2+t}\]

Answer 12

it goes like that

Answer 13

\[\frac{1}{t}-\frac{1}{t^2+t}=\frac{t^2+t}{t(t^2+t)}-\frac{t}{t(t^2+t)}=\frac{t^2}{t(t^2+t)}=\frac{t}{t^2+t}\]

Answer 14

A factor of \(t\) disappears on top and bottom, leaving you with
\[\frac{1}{t+1}\]

Answer 15

No, limits are defined for all cases. Either it will result in the value being approached, or it will result in there being no approached value.

Answer 16

I used t (t+1) as LCD that's why I got the answer wrong...btw Thanks to all of you guys!!!