Given ΔLMN where the length of segment NP is greater than the length of segment LP, the following is an indirect paragraph proof proving segment MP is not a median:
Assume segment MP is a median. According to the definition of a median, point P is the midpoint of side L N. By the definition of a midpoint NP = LP. This contradicts the given statement. Therefore, segment MP is not a median.
Is the indirect proof logically valid? If so, why? If not, why not? Yes. Statements are presented in a logical order using the correct theorems. Yes. The conclusion was used to contradict the assumption. No. The conclusion was used to contradict the assumption. No. The progression of the statements is logically inaccurate.
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wanna prove that \(NP \neq LP\)
Yes
since the the mediann devide the opposite side
I'm not so good at this...
its only hypotheses we dint start proving yet ^_^
ok nw we'll start , do you know what the median is ?
P
No, MP... I think
In geometry, a median of a triangle is a line segment joining a vertex to the midpoint of the opposing side. Every triangle has exactly three medians: one running from each vertex to the opposite side. In the case of isosceles and equilateral triangles, a median bisects any angle at a vertex whose two adjacent sides are equal in length.
like this |dw:1403378223466:dw|
Ok
so the Qn want to prove that MP is not median |dw:1403378276586:dw|
Right
lets use contradiction , and assume that MP is median
according to the definition of median above , then LP=PM |dw:1403378389180:dw|
Ok
so we have to statment PL< PN (given) PL= PN (proved ) and that make a contradiction so our assumtion that MP is median is wrong so MP is not median
So the answer is B?
I think. Right?
yes , ur correct ^_^
Thanks a ton!
remember this , having two statment that contradict each others means contradiction proving ok ?
Got it
np ! ur wlc ^_^
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