Question

help?
picture belowww

Answer 1

\(\bf {\color{brown}{ f(x)}}=\cfrac{4}{5}x+4\qquad g(x)=4x+5
\\ \quad \\
g(\quad {\color{brown}{ f(x)}}\quad )=4{\color{brown}{ f(x)}}+5\implies g(\quad {\color{brown}{ f(x)}}\quad )=4\left({\color{brown}{ \cfrac{4}{5}x+4}}\right)+5
\\ \quad \\ \quad \\
15\ biscuits\implies f({\color{blue}{ 15}})\qquad thus
\\ \quad \\
g(\quad {\color{brown}{ f({\color{blue}{ 15}})}}\quad )=4\left({\color{brown}{ \cfrac{4}{5}\cdot {\color{blue}{ 15}}+4}}\right)+5\)

Answer 2

would it be 4 4/5 ?

Answer 3

hmm well... ahemm nope... recall your PEMDAS :)

Answer 4

so i add 15 and 4 but what happenes when i distribute 4 and 4/5?

Answer 5

\(\bf 4\left({\color{brown}{ \cfrac{4}{\cancel{ 5 }}\cdot {\color{blue}{ \cancel{ 15 }}}+4}}\right)+5\)

Answer 6

you're missing the 15 factor, and recall, PEMDAS
multiplication first, then addition

Answer 7

8+8+5?

Answer 8

well.. \(\bf
4\left(\cfrac{4}{5}\cdot 15+4\right)+5\implies
4\left(\cfrac{4\cdot 15}{5}+4\right)+5\implies 4\left(\cfrac{60}{5}+4\right)+5\)

Answer 9

48+16+5?

Answer 10

yeap

Answer 11

thank you !

Answer 12

yw