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Mathematics 65 Online
OpenStudy (anonymous):

New problem! Picture attached below :) @saifoo.khan @jdoe0001 @Johnbc

OpenStudy (anonymous):

OpenStudy (anonymous):

A. looks like the most relevant answer

OpenStudy (anonymous):

wats ur opinion

OpenStudy (anonymous):

Between A & B

OpenStudy (the_fizicx99):

I don't think it's A, could be B.

OpenStudy (anonymous):

We can evaluate the expression from its exponential notation form to its actual numerical value and find \[(2 \times 10^{-3}) = 0.002\] This tells us we are dealing with something in the Thousandths place which is quite small

OpenStudy (anonymous):

^Correct, so I'm trying to figure out does it have to equal 0.002 ?

OpenStudy (anonymous):

If we were to assume it is the diameter of an atom we know that we can still readily "see" the number 0.002 but can we "see" the diameter of an atom?

OpenStudy (anonymous):

In the idea of measurements

OpenStudy (anonymous):

Not does not have to be exact just an estimate

OpenStudy (anonymous):

no, we can't. Therefore, we can eliminate A?

OpenStudy (anonymous):

We are actually given Units for the 2 answer choices as well so if we convert them to its relevant units where we do not have exponential notation then we can see our answer. If we apply the value to A. \[(2 \times 10^{-3}) meters = 2 millimeters\] Applied to B \[(2 \times 10^{-3}) Seconds = 2 Milliseconds\] Which seems more reasonable?

OpenStudy (anonymous):

Correct you can eliminate A

OpenStudy (anonymous):

Beautiful, you're sooo smart; It has to be B!

OpenStudy (anonymous):

Correct! Thank you but you have earned the credit for getting this far and great job!

OpenStudy (anonymous):

^Thanks, I have 2 more I need help with.

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