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Mathematics 13 Online
OpenStudy (anonymous):

In words, explain the difference in solving for x in the following situations: x squared = 121 and x = the square root of 121. I'm supposed to use this website to find the answer: http://tiny.cc/50wthx @jdoe0001 @jim_thompson5910 @saifoo.khan

jimthompson5910 (jim_thompson5910):

x^2 = 121 we want x all by itself

jimthompson5910 (jim_thompson5910):

how do we isolate x

OpenStudy (anonymous):

we square root it to remove the squared portion of "x"

jimthompson5910 (jim_thompson5910):

good, square root both sides \[\Large x^2 = 121\] \[\Large \sqrt{x^2} = \pm\sqrt{121}\] \[\Large x = \pm\sqrt{121}\] the plus/minus is there because x^2 = 121 has two solutions

jimthompson5910 (jim_thompson5910):

what's the next step?

OpenStudy (anonymous):

^not sure..

jimthompson5910 (jim_thompson5910):

what's the square root of 121?

OpenStudy (anonymous):

11

jimthompson5910 (jim_thompson5910):

good, square root both sides \[\Large x^2 = 121\] \[\Large \sqrt{x^2} = \pm\sqrt{121}\] \[\Large x = \pm\sqrt{121}\] \[\Large x = \pm 11\] the plus/minus is there because x^2 = 121 has two solutions

jimthompson5910 (jim_thompson5910):

\[\Large x = \pm 11\] turns into \(\Large x = 11\) or \(\Large x = -11\) which are the two solutions to \(\Large x^2 = 121\)

jimthompson5910 (jim_thompson5910):

notice how 11^2 = 121 and how (-11)^2 = 121 so they both satisfy the quadratic equation

OpenStudy (anonymous):

yes; but I need an actual explanation is words..

jimthompson5910 (jim_thompson5910):

well I just wrote what's going on

jimthompson5910 (jim_thompson5910):

we're taking the square root of both sides

jimthompson5910 (jim_thompson5910):

there's the plus/minus because 11^2 = 121 and (-11)^2 = 121

OpenStudy (anonymous):

no, I have to provide the whole answer in words..

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

ok well translate what I wrote into words

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