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Mathematics 10 Online
OpenStudy (anonymous):

PLEASE HELP!!!!!!!

OpenStudy (anonymous):

OpenStudy (anonymous):

Part A: What does the x-intercept of the function for car 1 represent? Part B: What does the y-intercept of the function for car 2 represent? Part C: What is the domain of the functions for car 1 and car 2? Part D: What is the average rate of change from x = 20 to x = 40 for the function representing the motion for car 2? What does the value of this average rate of change represent?

OpenStudy (anonymous):

Okay, let's begin. :D

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

If x is the distance, and y is the time, then they are driving somewhere. As time passes, they get closer, thus, the distance decreases. So what do you think happens when x = 0?

OpenStudy (anonymous):

They reached the destination

OpenStudy (anonymous):

?

OpenStudy (anonymous):

Yup! :D

OpenStudy (anonymous):

So what do you think the y intercept means?

OpenStudy (anonymous):

They started driving?

OpenStudy (anonymous):

Correct. You're smarter than you think you are. :)

OpenStudy (anonymous):

:)

OpenStudy (anonymous):

So what about part C?

OpenStudy (anonymous):

Do you know what a domain means?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

Okay, the domain is like the true values of something. For example, I can't have - 4 apples.

OpenStudy (anonymous):

I could have 0, or any number of positive integers.

OpenStudy (anonymous):

Do you see what I mean?

OpenStudy (anonymous):

yeah :)

OpenStudy (anonymous):

So, while the cars can drive in reverse, can they travel backwards through time?

OpenStudy (anonymous):

no ;)

OpenStudy (anonymous):

So x can't ever = -x

OpenStudy (anonymous):

no ;)

OpenStudy (anonymous):

So there is your domain.

OpenStudy (anonymous):

But you should write it as "x cannot be a negative value."

OpenStudy (anonymous):

oh, thanks ;)

OpenStudy (anonymous):

Now for the last one.

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Part D: What is the average rate of change from x = 20 to x = 40 for the function representing the motion for car 2? What does the value of this average rate of change represent?

OpenStudy (anonymous):

ok. so what do i do?

OpenStudy (anonymous):

Let me input the equation in here for you.

OpenStudy (anonymous):

\[A(x) = \frac{ f(b) - f(a) }{ b - a }\]

OpenStudy (anonymous):

Now we plug in and solve for A(x).

OpenStudy (anonymous):

ok. so what do u plug in ?

OpenStudy (anonymous):

20 and 40. :D b = 20 a = 40

OpenStudy (anonymous):

Want me to write the equation out so you can put it on paper?

OpenStudy (anonymous):

sure

OpenStudy (anonymous):

\[A(x) = \frac{ f(20) - f(40) }{ 20 - 40 }\]

OpenStudy (anonymous):

hold on, let me figure this out

OpenStudy (anonymous):

You can't figure it out yet, I just wanted you to write that down. xD

OpenStudy (anonymous):

We've gotta solve for f(20) and f(40) so we can replace those values.

OpenStudy (anonymous):

You there?

OpenStudy (anonymous):

ya :)

OpenStudy (anonymous):

Okay, so we need to create our function for the graph.

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

Hmm, I can't remember how to find the slope of a curved line.

OpenStudy (anonymous):

@Hero can you help me help Rosie please? :D

OpenStudy (anonymous):

@dan815

OpenStudy (anonymous):

Well I'm tired and I don't remember how to calculate the slope of a curved line. O.O

OpenStudy (anonymous):

Just ask that last part as a separate question and @ hero and dan.

OpenStudy (anonymous):

ok. well thank 4 your help :)

OpenStudy (anonymous):

No problem buddy. :)

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